2y^2+8y-6y=10

Solution for 2y^2+8y-6y=10 equation:

2y^2+8y-6y=10

We move all terms to the left:

2y^2+8y-6y-(10)=0

We add all the numbers together, and all the variables

2y^2+2y-10=0

a = 2; b = 2; c = -10;
Δ = b2-4ac
Δ = 22-4·2·(-10)
Δ = 84
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{84}=\sqrt{4*21}=\sqrt{4}*\sqrt{21}=2\sqrt{21}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{21}}{2*2}=\frac{-2-2\sqrt{21}}{4}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{21}}{2*2}=\frac{-2+2\sqrt{21}}{4}
$